Java Hibernate OneToOne Exception Mapping Error? -

i have follow classes

@entity @table(name = "seek") public class seek implements  serializable {      @id     @generatedvalue(strategy = generationtype.identity)     private int id;      @notnull     @valid     @onetoone(mappedby="url")     private url url;  }  @entity @table(name = "url") public class url implements serializable {      @id     @generatedvalue(strategy = generationtype.identity)     private int id;      @onetoone(cascade = cascadetype.all)     @joincolumn(name = "idseek", referencedcolumnname = "id")     private seek seek;  } 

my url table has idseek column, seek table doesn't have relationship column url table.

the exception receive is:

org.springframework.beans.factory.beancreationexception: error creating bean name 'seekdao': injection of autowired dependencies failed; nested exception org.springframework.beans.factory.beancreationexception: not autowire field: private org.hibernate.sessionfactory dao.hibernate.abstractdao.sessionfactory; nested exception org.springframework.beans.factory.beancreationexception: error creating bean name 'sessionfactory' defined in class path resource [configuration/hibernateconfig.class]: invocation of init method failed; nested exception org.hibernate.annotationexception: referenced property not (one|many)toone: model.url.url in mappedby of model.seek.url 

my daos extend

public abstract class abstractdao<pk extends serializable, t> {  private final class<t> persistentclass;  public abstractdao() {     this.persistentclass = (class<t>) ((parameterizedtype) this.getclass().getgenericsuperclass()).getactualtypearguments()[1]; }  @autowired private sessionfactory sessionfactory;  protected session getsession() {     return this.sessionfactory.getcurrentsession(); }  public t getbykey(pk key) {     return (t) this.getsession().get(this.persistentclass, key); }  public t getbycolumn(string column, string value) {     criteria criteria = this.getsession().createcriteria(this.persistentclass);     return (t) criteria.add(restrictions.eq(column, value)).uniqueresult(); }  public void persist(t entity) {     this.getsession().persist(entity); }  public void delete(t entity) {     this.getsession().delete(entity); }  protected criteria createentitycriteria() {     return this.getsession().createcriteria(this.persistentclass); }  protected query getquery(string query) {     return this.getsession().createquery(query); } 

}

like that

@repository("seekdao") public class seekdaoimpl extends abstractdao<integer, seek> implements seekdao {      @override     public seek get(int id) {         return super.getbykey(id);     }      @override     public void save(seek seek) {         super.persist(seek);     } } 

i don't know hibernate, problem?

edited

i did it, , compiles receive this: warn: sql error: 1048, sqlstate: 23000 error: column 'idseek' cannot null

my method @ service class is:

// service @transactional @override public void saveseek(seek seek) {     this.seekdao.save(seek);      this.urldao.save(seek.geturl());//the url inside seek obj } 

so need insert id manually , put @ url obj? thanks

your seek class not pointing correct mappedby property.

@entity @table(name = "seek") public class seek implements  serializable {      @id     @generatedvalue(strategy = generationtype.identity)     private int id;      @notnull     @valid     @onetoone(mappedby="seek")     private url url;  }