python - first date of week greater than x -

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i first monday in july greater july 10th list of dates, , wondering if there's elegant solution avoids loops/list comprehension. here code far gives july mondays greater 10th:

import pandas pd last_date = '08-jul-2016' monday2_dates=pd.date_range('1-jan-1999',last_date, freq='w-mon')  g1=pd.dataframe(1.0, columns=['dummy'], index=monday2_dates)  g1=g1.loc[(g1.index.month==7) & (g1.index.day>=10)]

iiuc can way:

get list of 2nd mondays within specified date range

in [116]: rng = pd.date_range('1-jan-1999',last_date, freq='wom-2mon')

filter them have in july day >= 10

in [117]: rng = rng[(rng.month==7) & (rng.day >= 10)]

create corresponding df

in [118]: df = pd.dataframe({'dummy':[1] * len(rng)}, index=rng)  in [119]: df out[119]:             dummy 1999-07-12      1 2000-07-10      1 2003-07-14      1 2004-07-12      1 2005-07-11      1 2006-07-10      1 2008-07-14      1 2009-07-13      1 2010-07-12      1 2011-07-11      1 2014-07-14      1 2015-07-13      1

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