Differentiating between Binary semaphore and Mutex using same code -

void forward(void *pvparam) {     while(1)     {         if(xsemaphoretake(xsemaphore,1000)==pdtrue)         {             uart0_sendstr("frwd took it\n");         }         else         {              uart0_sendstr("frwd couldn't take it\n");         }         vtaskdelay(1000);     } }  void back(void *pvparam) {     vtaskdelay(100);     while(1)     {         if(xsemaphoregive(xsemaphore)==pdtrue)         {             uart0_sendstr("back gave it:mf\n");         }         else         {              uart0_sendstr("back couldn't give it:ms\n");         }         vtaskdelay(1000);     } } 

above code 1 using both binary semaphore , mutex. difference binary semaphore writing "xsemaphorecreatebinary(xsemaphore);" in main , mutex xsemaphorecreatemutex(xsemaphore) in main.

according definetion

"a semaphore(mutex) occupied task can given task , semaphore(binary) created task can given of tasks"

but both codes(i.e binary semaphore , mutex) giving same output.

mutexes used controlling exclusive access resources / data. if take mutex protecting resource / data, must give when have finished, otherwise permanently block resource. mutexes allow priority inheritance.

binary semaphores on other hand used task synchronization purposes. not give give semaphore once have taken it.

looking @ code above think binary semaphore way go.