matlab - extract elements between two number from a matrix/vector -

for example, have 4x4 matrix

   = [1,    2,    3,    4;         2,    1,    4,    3;         1,    2,    4,    3;         4,    1,    2,    3;]; 

for each row, want extract elements between 1 , 3 (assume matrix has elements between 1 , 3, , 1 comes before 3). example, return cell [{2}, {4}, {2,4}, {2}], or better matrix

b=  [0,    1,    0,    0;      0,    0,    0,    1;      0,    1,    0,    1;      0,    1,    0,    0;]; 

now doing loop each row, find index of 1 , 3, set index between them zero, i.e.,

    b = zeros(4,4);     = 1 : size(a,1)         ind1 = find(a(i,:) ==1);         ind2 = find(a(i,:) ==3);         b(i, a(i,ind1+1:ind2-1) ) = 1;     end 

any easier way generate matrix b or cell? suggestion appreciated.

okay, might not easier solution, remove loop, should computationally faster:

the idea instead of trying find numbers between 1 , 3 , set them 1, going find numbers outside 1 , 3 , set 0:

b=zeros(4,4); b(a == 1) = 1; b(a == 3) = 1; c = cumsum(b')'; b(c>=2) =1; b(c< 1) =1;  %finally want invert this: b = (b-1)*-1;  >> b =   0     1     0     0  0     0     1     0  0     1     1     0  0     0     1     0 

========== part applies after second edit ==========

 d = a.*b % seems cell indexes after?   d =   0     2     0     0  0     0     4     0  0     2     4     0  0     0     2     0  e = zeros(4,4); t = 1:size(a,1)    e(t,d(t,d(t,:)>0)) = 1;  %this re-applies index numbers , create new index matrix through loop........    %or can use e(t,d(t,~~d(t,:))) = 1 same effect, @dev-il end   >> e =   0     1     0     0  0     0     0     1  0     1     0     1  0     1     0     0 

this give indexes of elements between 1 , 3 a, can use logical indexes find cell numbers want.