c# - How to show an image in imagebox and specify a value for combo when i select a row of dateagrid? -

i field of table , show them in datagrid code:

in xaml:

<datagrid x:name="dgvaddpersontab"  height="158" width="396" autogeneratecolumns="false" canuserdeleterows="false" selectionchanged="dgvaddpersontab_selectionchanged" canvas.left="520" canvas.top="20">     <datagrid.columns>         <datagridtextcolumn  binding="{binding firstname}" width="78" />         <datagridtextcolumn  binding="{binding family}" width="80" />         <datagridtextcolumn  binding="{binding departmentname}" width="78" />         <datagridtextcolumn  binding="{binding occupation}" width="80" />         <datagridtextcolumn  binding="{binding personalcardno}" width="78" />     </datagrid.columns> </datagrid> 

and in code behind:

var queryofdgvaddperson = j in facedb.tblknownpeoples                                       join m in facedb.tbldepartments                                       on j.iddepartment equals m.iddepartment                                       select new { j.firstname, j.family, m.departmentname, j.occupation, j.personalcardno, j.birthdate, j.fathername, j.fifthpicaddress, j.firstpicaddress, j.fourthpicaddress, j.iddepartment, j.nationalidcardno, j.phone, j.secondpicaddress, j.thirdpicaddress };              dgvaddpersontab.itemssource = queryofdgvaddperson.tolist(); 

now, want when select row in datagrid, fields corresponding row in table shown in textbox , combo , imagebox. can fields follow code:

object ob = datagrid.selecteditem; 

but can't show them, have problem combo , imagebox. must in field corresponding imagebox saved address of image.

updated: found way show string fetch table in textbox can't still have found way show image address , combovalue.

public ienumerable<datagridrow> getdatagridrows(datagrid grid)     {         var itemssource = grid.itemssource ienumerable;         if (null == itemssource) yield return null;         foreach (var item in itemssource)         {             var row = grid.itemcontainergenerator.containerfromitem(item) datagridrow;             if (null != row) yield return row;         }     }      private void dgvaddpersontab_selectionchanged(object sender, selectionchangedeventargs e)     {             var row_list = getdatagridrows(dgvaddpersontab);             foreach (datagridrow single_row in row_list)             {             if (single_row.isselected == true)             {                 txtname.text = convert.tostring(typedescriptor.getproperties(single_row.datacontext)["firstname"].getvalue(single_row.datacontext));              }             }     } 

second update:

suppose have 2 table named person , officeaccess. in person i'll save staffs of office , in officeaccess save access of staffs office's building. person has field: idknown, name, family, phone, idaccess , officeaccess has field: idaccess, accessdeccription. idaccess foreign key in person have reference officeaccess , idaccess column. now, after long intro(!), value of combo come officeaccess , accessdeccription.

i try follow code wrong:

cmbaccessofoffice.displaymemberpath = dgvaddpersonallfeilds.gettype().getproperty("departmentname").getvalue(dgvaddpersonallfeilds, null).tostring(); 

i think looking this

   var obj = dgvaddpersontab.selecteditem;             var nameofproperty = "departmentname";             var propertyinfo = obj.gettype().getproperty(nameofproperty);             var value = propertyinfo.getvalue(obj, null);                        img.source = new bitmapimage(new uri(value.tostring()));  

combobox:

when creating combobox need set selectedvaluepath.and can use same method above select combobox value

 var obj = dgvaddpersontab.selecteditem;                 var nameofproperty = "comoboxproperty";                 var propertyinfo = obj.gettype().getproperty(nameofproperty);                 var value = propertyinfo.getvalue(obj, null);  cmbaccessofoffice.selectedvalue=value ;